Match Quadratic Graphs and Their Equations: Mini-Lesson Review

Match Quadratic Graphs and Their Equations: Mini-Lesson Review

Match Quadratic Graphs and Their Equations: Mini-Lesson Review

Mini Lesson Question

Question #3: Match Quadratic Graphs and Their Equations

Examine the graph below.

GRAPH OF A PARABOLA THAT OPENS UPWARD WITH A \(y\)-intercepts OF NEGATIVE 3 AND \(x\)-intercepts OF NEGATIVE 1 AND 3.

Which function matches the graph?

  1. f ( x ) = ( x + 1 ) ( x + 3 )
  2. f ( x ) = ( x − 1 ) ( x − 3 )
  3. f ( x ) = ( x + 1 ) ( x − 3 )
  4. f ( x ) = ( x − 1 ) ( x + 3 )

Match Quadratic Graphs and Their Equations

The factored form helps find the zeros of a quadratic function.

The factored form gives the zeros, and the x x -intercepts are located where each factor equals 0.

Example

Examine the graph. What are the x x -intercepts of the graph?

Graph of a parabola that opens upward with a y-intercepts of negative 4 and x-intercepts of negative 4 and 1.

The graph crosses the x x -axis at x = − 4 x = − 4 and x = 1 x = 1 . These are the x x -intercepts.

Look at each function to see which matches the graph. Look for the factors that have zeros as x = − 4 x = − 4 and x = 1 x = 1 .

a. f ( x ) = ( x + 4 ) ( x + 1 ) f ( x ) = ( x + 4 ) ( x + 1 )

  • This function has zeros at x = − 4 x = − 4 and x = − 1 x = − 1 . The zero x = − 1 x = − 1 is not a zero on the graph.

b. f ( x ) = ( x − 4 ) ( x − 1 ) f ( x ) = ( x − 4 ) ( x − 1 )

  • This function has zeros at x = 4 x = 4 and x = 1 x = 1 . The zero x = 4 x = 4 is not a zero on the graph.

c. f ( x ) = ( x − 4 ) ( x + 1 ) f ( x ) = ( x − 4 ) ( x + 1 )

  • This function has zeros at x = 4 x = 4 and x = − 1 x = − 1 . The signs of the zeros of this function are the opposite of the signs of the zeros on the graph.

d. f ( x ) = ( x + 4 ) ( x − 1 ) f ( x ) = ( x + 4 ) ( x − 1 )

  • This function has zeros at x = − 4 x = − 4 and x = − 1 x = − 1 . This function has zeros that match the zeros on the graph.

The function f ( x ) = ( x + 4 ) ( x − 1 ) f ( x ) = ( x + 4 ) ( x − 1 ) matches the graph.

Try it

Match Quadratic Graphs and Their Equations

Examine the graph.

Graph of a parabola that opens upward with a y-intercepts of negative 8 and x-intercepts of negative 2 and 4.

Which function matches the graph?

a. f ( x ) = ( x + 2 ) ( x + 4 ) f ( x ) = ( x + 2 ) ( x + 4 )

b. f ( x ) = ( x − 2 ) ( x − 4 ) f ( x ) = ( x − 2 ) ( x − 4 )

c. f ( x ) = ( x + 2 ) ( x − 4 ) f ( x ) = ( x + 2 ) ( x − 4 )

d. f ( x ) = ( x − 2 ) ( x + 4 ) f ( x ) = ( x − 2 ) ( x + 4 )

Here’s how to match the function to the graph.

Look at each function to see which matches the graph. Look for the factors that have zeros at x = − 2 x = − 2 and x = 4 x = 4 .

a. f ( x ) = ( x + 2 ) ( x + 4 ) f ( x ) = ( x + 2 ) ( x + 4 )

  • This function has zeros at x = − 2 x = − 2 and x = − 4 x = − 4 . The zero x = − 4 x = − 4 is not a zero on the graph.

b. f ( x ) = ( x − 2 ) ( x − 4 ) f ( x ) = ( x − 2 ) ( x − 4 )

  • This function has zeros at x = 2 x = 2 and x = 4 x = 4 . The zero x = 2 x = 2 is not a zero on the graph.

c. f ( x ) = ( x + 2 ) ( x − 4 ) f ( x ) = ( x + 2 ) ( x − 4 )

  • This function has zeros at x = − 2 x = − 2 and x = 4 x = 4 . This function has zeros that match the zeros on the graph.

d. f ( x ) = ( x − 2 ) ( x + 4 ) f ( x ) = ( x − 2 ) ( x + 4 )

  • This function has zeros at x = 2 x = 2 and x = − 4 x = − 4 . The zeros of the function have the opposite signs of the zeros on the graph.

The function f ( x ) = ( x + 2 ) ( x − 4 ) f ( x ) = ( x + 2 ) ( x − 4 ) matches the graph.

Check Your Understanding

Examine the graph.

Graph of a parabola that opens upward with a y-intercepts of negative 6 and x-intercepts of negative 3 and 2.

Which function matches the graph?

  1. f ( x ) = ( x − 3 ) ( x − 2 ) f ( x ) = ( x − 3 ) ( x − 2 )

  2. f ( x ) = ( x − 3 ) ( x + 2 ) f ( x ) = ( x − 3 ) ( x + 2 )

  3. f ( x ) = ( x + 3 ) ( x − 2 ) f ( x ) = ( x + 3 ) ( x − 2 )

  4. f ( x ) = ( x + 3 ) ( x + 2 ) f ( x ) = ( x + 3 ) ( x + 2 )

f ( x ) = ( x + 3 ) ( x − 2 ) f ( x ) = ( x + 3 ) ( x − 2 )

Check yourself: Looking at the graph, the parabola has zeros at x = − 3 x = − 3 and x = 2 x = 2 . We can use the zero pairs of these values to determine the binomial factors for the x + 3 x + 3 function: and x − 2 x − 2 . The function f ( x ) = ( x + 3 ) ( x − 2 ) f ( x ) = ( x + 3 ) ( x − 2 ) has zeros at x = − 3 x = − 3 and x = 2 x = 2 .