Equations and Their Graphs

5.12.2 Equations and Their Graphs

5.12.2 • Equations and Their Graphs

Activity

Access the Desmos guide PDF for tips on solving problems with the Desmos graphing calculator.

1. Each of the following functions, f f , g g , h h , and j j , represents the amount of money in a bank account, in dollars, as a function of time x x , in years. They are each written in the form m ( x ) = a · b x m ( x ) = a · b x .

  • f ( x ) = 50 · 2 x f ( x ) = 50 · 2 x
  • g ( x ) = 50 · 3 x g ( x ) = 50 · 3 x
  • h ( x ) = 50 · ( 3 2 ) x h ( x ) = 50 · ( 3 2 ) x
  • j ( x ) = 50 · ( 0.5 ) x j ( x ) = 50 · ( 0.5 ) x

a. Use graphing technology to graph each function on the same coordinate plane. It may be helpful to use a different color for each function.

Compare your answers:

 

A graph with four labeled curves: f (orange), g (blue), h (green), and j (brown). All intersect near (0, 50); f, g, and h curve upward, while j curves downward as x increases from 0 to 4.

b. Explain how changing the value of b b  changes the graph.

Compare your answer:

When b b is greater than 1, larger values of b b mean that the function grows more quickly as x x increases. A positive value of b b that is less than 1 means the function is decreasing as x x increases.

2. Here are equations defining functions p p , q q , and r r . They are also written in the form m ( x ) = a · b x m ( x ) = a · b x .

  • p ( x ) = 10 · 4 x p ( x ) = 10 · 4 x
  • q ( x ) = 40 · 4 x q ( x ) = 40 · 4 x
  • r ( x ) = 100 · 4 x r ( x ) = 100 · 4 x

a. Use graphing technology to graph each function on the same coordinate plane. It may be helpful to use a different color for each function.

Compare your answers:

 

A graph with three exponential curves labeled p, q, and r, each in a different color, increasing steeply to the right on a grid with x- and y-axes marked, and y-values ranging from 0 to over 200.

b. Explain how changing the value of a a changes the graph.

Compare your answer:

It changes the y y -intercept to ( 0 , a ) ( 0 , a ) .

3. Here are equations defining functions f f , g g , and h h  written in the form m ( x ) = a · b x + d m ( x ) = a · b x + d .

  • f ( x ) = 4 x + 2 f ( x ) = 4 x + 2
  • g ( x ) = 4 x g ( x ) = 4 x
  • h ( x ) = 4 x − 2 h ( x ) = 4 x − 2

a. Use graphing technology to graph each function on the same coordinate plane. It may be helpful to use a different color for each function.

Compare your answers:

A graph showing three curves: f (red), g (black), and h (teal). All pass through (0,1); f increases fastest, h slowest as x increases. The x- and y-axes are labeled.

b. Discuss with a partner how changing the value of d d  changes the asymptote of the graph.

Compare your answer:

Changing the value of d d changes the horizontal asymptote from y = 0 y = 0 to y = d y = d . So function f ( x ) f ( x ) has a horizontal asymptote of y = 2 y = 2 , and h ( x ) h ( x ) has a horizontal asymptote of y = − 2 y = − 2 .

Are you ready for more?

Extending Your Thinking

As before, consider bank accounts whose balances are given by the following functions:

f ( x ) = 10 · 3 x f ( x ) = 10 · 3 x

g ( x ) = 3 x + 2 g ( x ) = 3 x + 2

h ( x ) = 1 2 · 3 x + 3 h ( x ) = 1 2 · 3 x + 3

Which function would you choose? Does your choice depend on x x ?

Compare your answer:

We can rewrite each of the functions as multiples of 3 x 3 x to more easily compare them:

f ( x ) = 10 · 3 x f ( x ) = 10 · 3 x

g ( x ) = 3 x + 2 = 3 x · 3 2 = 9 · 3 x g ( x ) = 3 x + 2 = 3 x · 3 2 = 9 · 3 x

h ( x ) = 1 2 · 3 x + 3 = 1 2 · 3 x · 3 3 = 27 2 · 3 x = ( 13.5 ) · 3 x h ( x ) = 1 2 · 3 x + 3 = 1 2 · 3 x · 3 3 = 27 2 · 3 x = ( 13.5 ) · 3 x

Since 9 < 10 < 13.5 9 < 10 < 13.5 , we see that h h  has the most money for any value of x x .

Video: Exponential Equations and How They Affect the Graphs

Watch the following video to learn more about exponential functions and how they affect the graphs:

Self Check

What is the horizontal asymptote for the function f ( x ) = 2 ⋅ 3 x − 5 ?
  1. y = 3
  2. y = − 5
  3. y = 2
  4. y = 5

Additional Resources

Vertical Shifts with Exponential Functions

The first transformation occurs when we add a constant d d  to the parent function f ( x ) = b x f ( x ) = b x , giving us a vertical shift d d  units in the same direction as the sign. For example, if we begin by graphing a parent function, f ( x ) = 2 x f ( x ) = 2 x , we can then graph two vertical shifts alongside it, using  d = 3 d = 3 : the upward shift, g ( x ) = 2 x + 3 g ( x ) = 2 x + 3 , and the downward shift, h ( x ) = 2 x − 3 h ( x ) = 2 x − 3 . Both vertical shifts are shown in the graph below.

Graph of three exponential growth functions. f of x has a y-intercept of 1 and a horizontal asymptote of y equals 0. g of x has a y-intercept of 4 and a horizontal asymptote of y equals 3. h of x has a y-intercept of negative 2 and a horizontal asymptote of y equals negative 3.

Observe the results of shifting f ( x ) = 2 x f ( x ) = 2 x vertically:

  • The domain,  ( − ∞ , ∞ ) ( − ∞ , ∞ ) , remains unchanged.
  • When the function is shifted up 3 units to g ( x ) = 2 x + 3 g ( x ) = 2 x + 3 :
    • The y y -intercept shifts up 3 units to ( 0 , 4 ) ( 0 , 4 ) .
    • The asymptote shifts up 3 units to y = 3 y = 3 .
    • The range becomes ( 3 , ∞ ) ( 3 , ∞ ) .
  • When the function is shifted down 3 units to h ( x ) = 2 x − 3 h ( x ) = 2 x − 3 :
    • The y y -intercept shifts down 3 units to ( 0 , − 2 ) ( 0 , − 2 ) .
    • The asymptote also shifts down 3 units to y = − 3 y = − 3 .
    • The range becomes ( − 3 , ∞ ) ( − 3 , ∞ ) .

Try it

Vertical Shifts with Exponential Functions

Where would the horizontal asymptote be located for the graph of f ( x ) = 4 · 2 x − 6 f ( x ) = 4 · 2 x − 6 ?

Compare your answer:

Here is how to find the equation of the horizontal asymptote:

In the function f ( x ) = 4 · 2 x − 6 f ( x ) = 4 · 2 x − 6 , the vertical shift is represented by –6.

The parent function, f ( x ) = 2 x f ( x ) = 2 x , has a horizontal asymptote at y = 0 y = 0 . For the function f ( x ) = 4 · 2 x − 6 f ( x ) = 4 · 2 x − 6 , the horizontal asymptote will be shifted down 6 to y = − 6 y = − 6 .