Writing Quadratics When Given Any Format

8.11.4 Writing Quadratics When Given Any Format

8.11.4 • Writing Quadratics When Given Any Format

Cool Down

In this lesson, you have learned how to write a quadratic function from different starting contexts and when provided different information.

1.

Identify a quadratic function in standard form, b ( x ) b(x), with the zeros –6 and 8.

Compare your answer:

b ( x ) = x 2 − 2 x − 48 b(x)= x 2 −2x−48

2.

Identify a quadratic function in standard form, m ( x ) m(x), with the given zero.

A PARABOLA THAT OPENS UP WITH AN \(x\)-intercepts OF 6.

Compare your answer:

m ( x ) = x 2 − 12 x + 36 m(x)= x 2 −12x+36

3.

Write the specific quadratic function, d ( x ) d(x), in standard form, that has the zeros 2 and 5 and passes through the point ( 1 , 16 ) (1,16).

Compare your answer:

Intercept form: d ( x ) = a ( x − 2 ) ( x − 5 ) d(x)=a(x−2)(x−5)

Find the value of a a. Use point ( 1 , 16 ) (1,16).

d ( x ) = a ( x − 2 ) ( x − 5 ) d(x)=a(x−2)(x−5)

16 = a ( ( 1 ) − 2 ) ( ( 1 ) − 5 ) 16=a((1)−2)((1)−5)

16 = a ( − 1 ) ( − 4 ) 16=a(−1)(−4)

16 = 4 a 16=4a

4 = a 4=a

Substitute 4 for aa.

d ( x ) = a ( x − 2 ) ( x − 5 ) d(x)=a(x−2)(x−5)

d ( x ) = 4 ( x − 2 ) ( x − 5 ) d(x)=4(x−2)(x−5)

d ( x ) = 4 ( x 2 − 2 x − 5 x + 10 ) d(x)=4( x 2 −2x−5x+10)

d ( x ) = 4 ( x 2 − 7 x + 10 ) d(x)=4( x 2 −7x+10)

d ( x ) = 4 x 2 − 28 x + 40 d(x)=4 x 2 −28x+40

So, the specific quadratic function written in standard form is d ( x ) = 4 x 2 − 28 x + 40 d(x)=4 x 2 −28x+40.