Using the Distributive Property to Write Equivalent Expressions

7.8.2 Using the Distributive Property to Write Equivalent Expressions

7.8.2 • Using the Distributive Property to Write Equivalent Expressions

Activity

Applying the distributive property to multiply out the factors of, or expand, 4 ( x + 2 ) 4 ( x + 2 ) gives us 4 x + 8 4 x + 8 , so we know the two expressions are equivalent. We can use a rectangle with side lengths ( x + 2 ) ( x + 2 ) and 4 to illustrate the multiplication.

An area model using a rectangle is divided into 2 smaller rectangles with a vertical segment. The top left section of the rectangle is labeled x and the top right of the rectangle is labeled 2. The side length of the rectangle is labeled 4. There are two areas inside the rectangle: The left portion of the rectangle bordered by the x and 4 is labeled 4 times x. The right portion of the rectangle bordered by the 2 (on top) is labeled with an 8.

1. Draw a diagram to show that n ( 2 n + 5 ) n ( 2 n + 5 ) and 2 n 2 + 5 n 2 n 2 + 5 n are equivalent expressions.

Compare your answer:

An area model using a rectangle is divided into 2 smaller rectangles with a vertical segment. The top left section of the rectangle is labeled 2 times n and the top right of the rectangle is labeled 5. The side length of the rectangle is labeled n. There are two areas inside the rectangle: The left portion of the rectangle bordered by the 2n and n is labeled 2 times n squared. The right portion of the rectangle bordered by the 5 (on top) is labeled with an 5 times n.

2. For each expression, use the distributive property to write an equivalent expression. If you get stuck, consider drawing a diagram.

a. 6 ( 1 3 n + 2 ) 6 ( 1 3 n + 2 )

Compare your answer:

2 n + 12 2 n + 12

b. p ( 4 p + 9 ) p ( 4 p + 9 )

Compare your answer:

4 p 2 + 9 p 4 p 2 + 9 p

c. 5 r ( r + 3 5 ) 5 r ( r + 3 5 )

Compare your answer:

5 r 2 + 3 r 5 r 2 + 3 r

d. ( 0.5 w + 7 ) w ( 0.5 w + 7 ) w

Compare your answer:

0.5 w 2 + 7 w 0.5 w 2 + 7 w

Self Check

Which expression is equivalent to 4 t ( t − 3 4 ) ?
  1. 4 t 2 − 3 4
  2. 4 t 2 − 3 t
  3. 4 t 2 − 3 4 t
  4. 4 t 2 − 3

Additional Resources

Distributive Property

Distributive Property

If a a , b b , c c are real numbers, then:

a ( b + c ) = a b + a c a ( b + c ) = a b + a c

Other forms:

a ( b − c ) = a b − a c a ( b − c ) = a b − a c

( b + c ) a = b a + c a ( b + c ) a = b a + c a

Example 1

Simplify 3 ( x + 4 ) 3 ( x + 4 )

Step 1 - Distribute the 3 to both the x x and the 4.

Diagram showing 3 multiplied times the quantity of x plus 4. An arrow is going from 3 to x. Another arrow is going from 3 to 4.

Step 2 - Multiply the terms.

3 ( x ) + 3 ( 4 ) 3 ( x ) + 3 ( 4 )

Step 3 - Simplify.

3 x + 12 3 x + 12

Example 2

Simplify m ( 7 − 2 m ) m ( 7 − 2 m )

Step 1 - Distribute the m m to both the 7 and the 2 m 2 m .

Diagram showing m multiplied times the quantity of 7 minus 2 times m. An arrow is going from m to 7. Another arrow is going from m to 2 times m.

Step 2 - Multiply the terms. Recall m · m = m 2 m · m = m 2 .

m ( 7 ) − m ( 2 m ) m ( 7 ) − m ( 2 m )

Step 3 - Simplify.

7 m − 2 m 2 7 m − 2 m 2

Example 3

Simplify 5 x ( x − 2 5 ) 5 x ( x − 2 5 )

Step 1 - Distribute the 5 x 5 x to both the x x and the 2 5 2 5 .

Diagram showing 5 times x multiplied times the quantity of x minus the fraction two-fifths. An arrow is going from 5 times x to x. Another arrow is going from 5 times x to two-fifths.

Step 2 - Multiply the terms. Recall x · x = x 2 x · x = x 2 .

5 x ( x ) − 5 x ( 2 5 ) 5 x ( x ) − 5 x ( 2 5 )

Step 3 - Simplify.

5 x 2 − 2 x 5 x 2 − 2 x

Try it

Distributive Property

Simplify 7 y ( 4 y − 3 7 ) 7 y ( 4 y − 3 7 )

Here is how to simplify the expression using the distributive property:

Step 1 - Distribute the 7 y 7 y to both the 4 y 4 y and the 3 7 3 7 .

Diagram showing 7 times y multiplied times the quantity of 4 times y minus the fraction three-sevenths. An arrow is going from 7 times y to 4 times y. Another arrow is going from 7 times y to three-sevenths.

Step 2 - Multiply the terms. Recall y · y = y 2 y · y = y 2 . 7 y ( 4 y ) − 7 y ( 3 7 ) 7 y ( 4 y ) − 7 y ( 3 7 )

Step 3 - Simplify. 28 y 2 − 3 y 28 y 2 − 3 y