Finding a Solution through Substitution

8.9.1 Finding a Solution through Substitution

8.9.1 • Finding a Solution through Substitution

Warm Up

Let's try to find at least one solution to x2−2x−35=0x2−2x−35=0.

1.

Create a table of values. In column 1, enter the whole numbers between 0 and 10 to represent values of xx. In column 2, evaluate the expression x2−2x−35x2−2x−35 using the values for xx.

Compare your answer:

xx 0 1 2 3 4 5 6 7 8 9 10
x2−2x−35x2−2x−35 –35 –36 –35 –32 –27 –20 –11 0 13 28 45
This table displays the values of x and the quadratic expression x^2 - 2x - 35 for integer values of x from 0 to 10.

We can see from the table that a solution to the equation is x=7x=7 since x2−2x−35=0x2−2x−35=0 at that value.

2.

There is another number outside of 0 to 10 that would make the expression x2−2x−35x2−2x−35 equal 0. Can you find it?

Compare your answer:

The other zero for the equation is located at x=−5x=−5, but it is possible that you did not consider negative numbers.