Arithmetic Sequences

12.2 Arithmetic Sequences

Learning Objectives

By the end of this section, you will be able to:

  • Determine if a sequence is arithmetic
  • Find the general term (nnth term) of an arithmetic sequence
  • Find the sum of the first nn terms of an arithmetic sequence

Be Prepared 12.4

Before you get started, take this readiness quiz.

Evaluate 4n−14n−1 for the integers 1, 2, 3, and 4.
If you missed this problem, review Example 1.6.

Be Prepared 12.5

Solve the system of equations: {x+y=73x+4y=23.{x+y=73x+4y=23.
If you missed this problem, review Example 4.9.

Be Prepared 12.6

If f(n)=n2(3n+5),f(n)=n2(3n+5), find f(1)+f(20).f(1)+f(20).
If you missed this problem, review Example 3.49.

Determine if a Sequence is Arithmetic

The last section introduced sequences and now we will look at two specific types of sequences that each have special properties. In this section we will look at arithmetic sequences and in the next section, geometric sequences.

An arithmetic sequence is a sequence where the difference between consecutive terms is constant. The difference between consecutive terms in an arithmetic sequence, an−an−1,an−an−1, is d, the common difference, for n greater than or equal to two.

Arithmetic Sequence

An arithmetic sequence is a sequence where the difference between consecutive terms is always the same.

The difference between consecutive terms, an−an−1,an−an−1, is d, the common difference, for n greater than or equal to two.

This figure has two rows and three columns. The first row reads “7”, “10”,”13”, “16”, “19”, “22”, and an ellipsis, “10 minus 7, divided by 3”, “13 minus 10, divided by 3”, “16 minus 13, divided by 3”, nth term equals nth term minus 1 divided by d”

In each of these sequences, the difference between consecutive terms is constant, and so the sequence is arithmetic.

Example 12.13

Determine if each sequence is arithmetic. If so, indicate the common difference.

ⓐ 5,9,13,17,21,25,…5,9,13,17,21,25,…

ⓑ 4,9,12,17,20,25,…4,9,12,17,20,25,…

ⓒ 10,3,−4,−11,−18,−25,…10,3,−4,−11,−18,−25,…

Solution

To determine if the sequence is arithmetic, we find the difference of the consecutive terms shown.

ⓐ




Find the difference of
the consecutive terms.
5,9,13,1721,25,… 9−513−917−1321−1725−21 444445,9,13,1721,25,… 9−513−917−1321−1725−21 44444
The sequence is arithmetic. The common difference is d=4.d=4.
Example of calculating the common difference for a given arithmetic sequence.


ⓑ




Find the difference of
the consecutive terms.
4,9,12,1720,25,… 9−412−917−1220−1725−20 535354,9,12,1720,25,… 9−412−917−1220−1725−20 53535
The sequence is not arithmetic as all the differences between
the consecutive terms are not the same.
There is no common difference.
This table demonstrates how to determine if a sequence is arithmetic by calculating consecutive term differences, concluding that the example sequence is not arithmetic.


ⓒ




Find the difference of
the consecutive terms.
10,3,−4,−11−18,−25,… 3−10−4−3−11−(−4)−18−(−11)−25−(−18) −7−7−7−7−710,3,−4,−11−18,−25,… 3−10−4−3−11−(−4)−18−(−11)−25−(−18) −7−7−7−7−7
The sequence is arithmetic. The common difference is d=−7.d=−7.
Demonstration of finding the common difference for an arithmetic sequence by subtracting consecutive terms, using a specific numerical example.

Try It 12.25

Determine if each sequence is arithmetic. If so, indicate the common difference.

ⓐ 9,20,31,42,53,64,…9,20,31,42,53,64,… ⓑ 12,6,0,−6,−12,−18,…12,6,0,−6,−12,−18,… ⓒ 7,1,10,4,13,7,…7,1,10,4,13,7,…

Try It 12.26

Determine if each sequence is arithmetic. If so, indicate the common difference.

ⓐ −4,4,2,10,8,16,…−4,4,2,10,8,16,… ⓑ −3,−1,1,3,5,7,…−3,−1,1,3,5,7,… ⓒ 7,2,−3,−8,−13,−18,…7,2,−3,−8,−13,−18,…

If we know the first term, a1,a1, and the common difference, d, we can list a finite number of terms of the sequence.

Example 12.14

Write the first five terms of the sequence where the first term is 5 and the common difference is d=−6.d=−6.

Solution

We start with the first term and add the common difference. Then we add the common difference to that result to get the next term, and so on.

a 1 a 2 a 3 a 4 a 5 5 5 + ( −6 ) −1 + ( −6 ) −7 + ( −6 ) −13 + ( −6 ) −1 −7 −13 −19 a 1 a 2 a 3 a 4 a 5 5 5 + ( −6 ) −1 + ( −6 ) −7 + ( −6 ) −13 + ( −6 ) −1 −7 −13 −19

The sequence is 5,−1,−7,−13,−19,…5,−1,−7,−13,−19,…

Try It 12.27

Write the first five terms of the sequence where the first term is 7 and the common difference is d=−4.d=−4.

Try It 12.28

Write the first five terms of the sequence where the first term is 11 and the common difference is d=−8.d=−8.

Find the General Term (nth Term) of an Arithmetic Sequence

Just as we found a formula for the general term of a sequence, we can also find a formula for the general term of an arithmetic sequence.

Let’s write the first few terms of a sequence where the first term is a1a1 and the common difference is d. We will then look for a pattern.

As we look for a pattern we see that each term starts with a1a1.

This figures shows an image of a sequence.

The first term adds 0d to the a1a1, the second term adds 1d, the third term adds 2d, the fourth term adds 3d, and the fifth term adds 4d. The number of ds that were added to a1a1 is one less than the number of the term. This leads us to the following

an=a1+(n−1)dan=a1+(n−1)d

General Term (nth term) of an Arithmetic Sequence

The general term of an arithmetic sequence with first term a1a1 and the common difference d is

an=a1+(n−1)dan=a1+(n−1)d

We will use this formula in the next example to find the 15th term of a sequence.

Example 12.15

Find the fifteenth term of a sequence where the first term is 3 and the common difference is 6.

Solution

To find the fifteenth term, a15,a15, use the
formula with a1=3andd=6.a1=3andd=6.
an=a1+(n−1)dan=a1+(n−1)d
Substitute in the values. a15=3+(15−1)6a15=3+(15−1)6
Simplify. a15=3+(14)6a15=3+(14)6
a15=87a15=87
Calculation of the 15th term of an arithmetic sequence using the formula a_n = a_1 + (n-1)d.

Try It 12.29

Find the twenty-seventh term of a sequence where the first term is 7 and the common difference is 9.

Try It 12.30

Find the eighteenth term of a sequence where the first term is 13 and the common difference is −7−7.

Sometimes we do not know the first term and we must use other given information to find it before we find the requested term.

Example 12.16

Find the twelfth term of a sequence where the seventh term is 10 and the common difference is −2−2. Give the formula for the general term.

Solution

To first find the first term, a1,a1, use the
formula with a7=10,n=7,andd=−2.a7=10,n=7,andd=−2.
an=a1+(n−1)dan=a1+(n−1)d
Substitute in the values. 10=a1+(7−1)(−2)10=a1+(7−1)(−2)
Simplify. 10=a1+(6)(−2)10=a1+(6)(−2)
10=a1−1210=a1−12
a1=22a1=22
Find the twelfth term, a12,a12, using the
formula with a1=22,n=12,andd=−2.a1=22,n=12,andd=−2.
an=a1+(n−1)dan=a1+(n−1)d
Substitute in the values. a12=22+(12−1)(−2)a12=22+(12−1)(−2)
Simplify. a12=22+(11)(−2)a12=22+(11)(−2)
a12=0a12=0
The twelfth term of the sequence is 0, a12=0.a12=0.
To find the general term, substitute
the values into the formula.
an=a1+(n−1)dan=a1+(n−1)d
an=22+(n−1)(−2)an=22+(n−1)(−2)
an=22−2n+2an=22−2n+2
The general term is an=−2n+24.an=−2n+24.
This table illustrates the step-by-step calculation for finding the first, 12th, and general terms of an arithmetic sequence.

Try It 12.31

Find the eleventh term of a sequence where the ninth term is 8 and the common difference is −3.−3. Give the formula for the general term.

Try It 12.32

Find the nineteenth term of a sequence where the fifth term is 1 and the common difference is −4.−4. Give the formula for the general term.

Sometimes the information given leads us to two equations in two unknowns. We then use our methods for solving systems of equations to find the values needed.

Example 12.17

Find the first term and common difference of a sequence where the fifth term is 19 and the eleventh term is 37. Give the formula for the general term.

Solution

Since we know two terms, we can make a system of equations using the formula for the general term.

The formula for the nth term of an arithmetic sequence, expressed as a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the term number, and d is the common difference.
We know the value of a5a5 and a11,a11, so we will use n=5n=5 and n=11.n=11. This image displays two equations representing specific terms of an arithmetic sequence. The first equation, a_5 = a_1 + (5 - 1)d, calculates the 5th term (a_5). The second equation, a_11 = a_1 + (11 - 1)d, calculates the 11th term (a_11). In both formulas, a_1 represents the first term of the sequence and d represents the common difference.
Substitute in the values, a5=19a5=19 and a11=37.a11=37. A system of two linear equations, 19 = a_1 + (5 - 1)d and 37 = a_1 + (11 - 1)d, used to find the first term (a_1) and common difference (d) of an arithmetic sequence. Key numbers are highlighted in red.
Simplify. A system of two linear equations is presented, with the first equation being 19 = a1 + 4d and the second equation being 37 = a1 + 10d, enclosed by a brace on the left.
Prepare to eliminate the a1a1 term by multiplying the top equation by −1.−1.
Add the equations.
This image illustrates the elimination method for solving a system of linear equations. By adding the two equations, 'a1' is eliminated, leading to 18 = 6d, and subsequently d = 3.

Substituting d=3d=3 back into the first equation.

The equation 19 = a₁ + 4 • 3 is displayed, where the dot multiplication sign and the number 3 are colored red.
Solve for a1.a1. A mathematical equation shown in two lines. The first line is 19 = a sub 1 + 12, and the second line is the solution, 7 = a sub 1.

Use the formula with a1=7a1=7 and d=3.d=3.

The image shows the formula for the nth term of an arithmetic progression, which is a_n = a_1 + (n-1)d.
Substitute in the values. The image shows the mathematical formula a_n = 7 + (n - 1)3, which represents an arithmetic sequence where a_n is the nth term, 7 is the first term, and 3 is the common difference.
Simplify. Two lines of mathematical equations showing the simplification of an algebraic expression: a_n = 7 + 3n - 3 is simplified to a_n = 3n + 4.
The first term is a1=7.a1=7.
The common difference is d=3.d=3.

The general term of the sequence is an=3n+4.an=3n+4.

Try It 12.33

Find the first term and common difference of a sequence where the fourth term is 17 and the thirteenth term is 53. Give the formula for the general term.

Try It 12.34

Find the first term and common difference of a sequence where the third term is 2 and the twelfth term is −25.−25. Give the formula for the general term.

Find the Sum of the First n Terms of an Arithmetic Sequence

As with the general sequences, it is often useful to find the sum of an arithmetic sequence. The sum, Sn,Sn, of the first nn terms of any arithmetic sequence is written as Sn=a1+a2+a3+...+an.Sn=a1+a2+a3+...+an. To find the sum by merely adding all the terms can be tedious. So we can also develop a formula to find the sum of a sequence using the first and last term of the sequence.

We can develop this new formula by first writing the sum by starting with the first term, a1,a1, and keep adding a d to get the next term as:

Sn=a1+(a1+d)+(a1+2d)+…+an.Sn=a1+(a1+d)+(a1+2d)+…+an.

We can also reverse the order of the terms and write the sum by starting with anan and keep subtracting d to get the next term as

Sn=an+(an–d)+(an–2d)+…+a1.Sn=an+(an–d)+(an–2d)+…+a1.

If we add these two expressions for the sum of the first n terms of an arithmetic sequence, we can derive a formula for the sum of the first n terms of any arithmetic series.

Sn=a1+(a1+d)+(a1+2d)+…+an+Sn=an+(an−d)+(an−2d)+…+a1_________________________________________________________2Sn=(a1+an)+(a1+an)+(a1+an)+…+(a1+an)Sn=a1+(a1+d)+(a1+2d)+…+an+Sn=an+(an−d)+(an−2d)+…+a1_________________________________________________________2Sn=(a1+an)+(a1+an)+(a1+an)+…+(a1+an)

Because there are n sums of (a1+an)(a1+an) on the right side of the equation, we rewrite the right side as n(a1+an).n(a1+an).

2Sn=n(a1+an)2Sn=n(a1+an)

We divide by two to solve for Sn.Sn.

Sn=n2(a1+an)Sn=n2(a1+an)

This gives us a general formula for the sum of the first n terms of an arithmetic sequence.

Sum of the First n Terms of an Arithmetic Sequence

The sum, Sn,Sn, of the first n terms of an arithmetic sequence is

Sn=n2(a1+an)Sn=n2(a1+an)

where a1a1 is the first term and anan is the nth term.

We apply this formula in the next example where the first few terms of the sequence are given.

Example 12.18

Find the sum of the first 30 terms of the arithmetic sequence: 8, 13, 18, 23, 28, …

Solution

To find the sum, we will use the formula Sn=n2(a1+an).Sn=n2(a1+an). We know a1=8a1=8, d=5d=5 and n=30,n=30, but we need to find anan in order to use the sum formula.

an=a1+(n−1)dan=a1+(n−1)d
Findanwherea1=8,d=5andn=30.Findanwherea1=8,d=5andn=30. a30=8+(30−1)5a30=8+(30−1)5
Simplify. a30=8+(29)5a30=8+(29)5
a30=153a30=153
Knowinga1=8,n=30,anda30=153,Knowinga1=8,n=30,anda30=153,
use the sum formula.
Sn=n2(a1+an)Sn=n2(a1+an)
Substitute in the values. S30=302(8+153)S30=302(8+153)
Simplify. S30=15(161)S30=15(161)
Simplify. S30=2,415S30=2,415
Illustrates the step-by-step calculation of the nth term and the sum of the first n terms for an arithmetic sequence.

Try It 12.35

Find the sum of the first 30 terms of the arithmetic sequence: 5, 9, 13, 17, 21, …

Try It 12.36

Find the sum of the first 30 terms of the arithmetic sequence: 7, 10, 13, 16, 19, …

In the next example, we are given the general term for the sequence and are asked to find the sum of the first 50 terms.

Example 12.19

Find the sum of the first 50 terms of the arithmetic sequence whose general term is an=3n−4.an=3n−4.

Solution

To find the sum, we will use the formula Sn=n2(a1+an).Sn=n2(a1+an). We know n=50,n=50, but we need to find a1a1 and anan in order to use the sum formula.

A mathematical equation is displayed on a white background: a subscript n equals 3n minus 4.
Find a1,a1, by substituting n=1.n=1. The calculation of the first term, a_1, from the expression 3 * 1 - 4, resulting in a_1 = -1. The value '1' is highlighted in red, indicating its substitution.
Find anan by substituting n=50.n=50. Mathematical expressions show the nth term of a sequence as a_n = 3n - 4, and its 50th term calculated as a_50 = 3 * 50 - 4, highlighting the substituted value 50.
Simplify. The mathematical equation a_50 = 146 is displayed on a white background, representing the 50th term of a sequence equaling 146.
Knowing n=50,n=50,a1=−1,a1=−1, and a50=146a50=146 use the sum formula. The formula for the sum of the first 'n' terms of an arithmetic sequence is shown: S_n = (n/2)(a_1 + a_n).
Substitute in the values. A mathematical equation for the sum of an arithmetic sequence, S_n = (50/2)(-1 + 146), which is S_n = 25 * 145.
Simplify. A mathematical equation shows S with a subscript 50, an equals sign, 25, and (145), indicating S_50 = 25(145).
Simplify. A mathematical equation S with a subscript 50, followed by an equals sign and the number 3,625, is displayed against a white background.

Try It 12.37

Find the sum of the first 50 terms of the arithmetic sequence whose general term is an=2n−5.an=2n−5.

Try It 12.38

Find the sum of the first 50 terms of the arithmetic sequence whose general term is an=4n+3.an=4n+3.

In the next example we are given the sum in summation notation. To add all the terms would be tedious, so we extract the information needed to use the formula to find the sum of the first n terms.

Example 12.20

Find the sum: ∑i=125(4i+7).∑i=125(4i+7).

Solution

To find the sum, we will use the formula Sn=n2(a1+an).Sn=n2(a1+an). We know n=25,n=25, but we need to find a1a1 and anan in order to use the sum formula.

Expand the summation notation. A mathematical equation shows the expansion of a summation expression from i=1 to 25 for (4i + 7), illustrating the first few terms and the last term of the series.
Simplify. A mathematical equation showing the expansion of the summation of 4i + 7 from i=1 to 25, resulting in the series 11 + 15 + 19 + ... + 107.
Identify a1.a1. A mathematical equation is displayed on a white background, reading 'a_1 = 11' in black text.
Identify a25.a25. A mathematical expression shows 'a sub 25 equals 107' on a plain white background.
Knowing n=25,n=25,a1=11,a1=11, and a25=107a25=107
use the sum formula.
A white background displays the mathematical formula S_n = n/2 (a_1 + a_n), which is used to calculate the sum of an arithmetic sequence, representing S sub n equals n over 2 times the quantity of a sub 1 plus a sub n.
Substitute in the values. A mathematical equation shows S_25 equals 25 divided by 2, multiplied by the sum of 11 and 107, representing the sum of an arithmetic series.
Simplify. A mathematical equation shows S subscript 25 equals 25 over 2 multiplied by 118, displayed in black text on a white background.
Simplify. The mathematical equation S₂₅ = 1,475 is displayed in black text against a plain white background, indicating a sum or a value for an indexed variable.

Try It 12.39

Find the sum: ∑i=130(6i−4).∑i=130(6i−4).

Try It 12.40

Find the sum: ∑i=135(5i−3).∑i=135(5i−3).

Media

Access these online resources for additional instruction and practice with arithmetic sequences

Section 12.2 Exercises

Practice Makes Perfect

Determine if a Sequence is Arithmetic

In the following exercises, determine if each sequence is arithmetic, and if so, indicate the common difference.

77.

4 , 12 , 20 , 28 , 36 , 44 , … 4 , 12 , 20 , 28 , 36 , 44 , …

78.

−7 , −2 , 3 , 8 , 13 , 18 , … −7 , −2 , 3 , 8 , 13 , 18 , …

79.

−15 , −16 , 3 , 12 , 21 , 30 , … −15 , −16 , 3 , 12 , 21 , 30 , …

80.

11 , 5 , −1 , −7 − 13 , −19 , … 11 , 5 , −1 , −7 − 13 , −19 , …

81.

8 , 5 , 2 , −1 , −4 , −7 , … 8 , 5 , 2 , −1 , −4 , −7 , …

82.

15 , 5 , −5 , −15 , −25 , −35 , … 15 , 5 , −5 , −15 , −25 , −35 , …

In the following exercises, write the first five terms of each sequence with the given first term and common difference.

83.

a1=11a1=11 and d=7d=7

84.

a1=18a1=18 and d=9d=9

85.

a1=−7a1=−7 and d=4d=4

86.

a1=−8a1=−8 and d=5d=5

87.

a1=14a1=14 and d=−9d=−9

88.

a1=−3a1=−3 and d=−3d=−3

Find the General Term (nth Term) of an Arithmetic Sequence

In the following exercises, find the term described using the information provided.

89.

Find the twenty-first term of a sequence where the first term is three and the common difference is eight.

90.

Find the twenty-third term of a sequence where the first term is six and the common difference is four.

91.

Find the thirtieth term of a sequence where the first term is −14−14 and the common difference is five.

92.

Find the fortieth term of a sequence where the first term is −19−19 and the common difference is seven.

93.

Find the sixteenth term of a sequence where the first term is 11 and the common difference is −6.−6.

94.

Find the fourteenth term of a sequence where the first term is eight and the common difference is −3.−3.

95.

Find the twentieth term of a sequence where the fifth term is −4−4 and the common difference is −2.−2. Give the formula for the general term.

96.

Find the thirteenth term of a sequence where the sixth term is −1−1 and the common difference is −4.−4. Give the formula for the general term.

97.

Find the eleventh term of a sequence where the third term is 19 and the common difference is five. Give the formula for the general term.

98.

Find the fifteenth term of a sequence where the tenth term is 17 and the common difference is seven. Give the formula for the general term.

99.

Find the eighth term of a sequence where the seventh term is −8−8 and the common difference is −5.−5. Give the formula for the general term.

100.

Find the fifteenth term of a sequence where the tenth term is −11−11 and the common difference is −3.−3. Give the formula for the general term.

In the following exercises, find the first term and common difference of the sequence with the given terms. Give the formula for the general term.

101.

The second term is 14 and the thirteenth term is 47.

102.

The third term is 18 and the fourteenth term is 73.

103.

The second term is 13 and the tenth term is −51.−51.

104.

The third term is four and the tenth term is −38−38.

105.

The fourth term is −6−6 and the fifteenth term is 27.

106.

The third term is −13−13 and the seventeenth term is 15.

Find the Sum of the First n Terms of an Arithmetic Sequence

In the following exercises, find the sum of the first 30 terms of each arithmetic sequence.

107.

11 , 14 , 17 , 20 , 23 , … 11 , 14 , 17 , 20 , 23 , …

108.

12 , 18 , 24 , 30 , 36 , … 12 , 18 , 24 , 30 , 36 , …

109.

8 , 5 , 2 , −1 , −4 , … 8 , 5 , 2 , −1 , −4 , …

110.

16 , 10 , 4 , −2 , −8 , … 16 , 10 , 4 , −2 , −8 , …

111.

−17 , −15 , −13 , −11 , −9 , … −17 , −15 , −13 , −11 , −9 , …

112.

−15 , −12 , −9 , −6 , −3 , … −15 , −12 , −9 , −6 , −3 , …

In the following exercises, find the sum of the first 50 terms of the arithmetic sequence whose general term is given.

113.

a n = 5 n − 1 a n = 5 n − 1

114.

a n = 2 n + 7 a n = 2 n + 7

115.

a n = −3 n + 5 a n = −3 n + 5

116.

a n = −4 n + 3 a n = −4 n + 3

In the following exercises, find each sum.

117.

∑ i = 1 40 ( 8 i − 7 ) ∑ i = 1 40 ( 8 i − 7 )

118.

∑ i = 1 45 ( 7 i − 5 ) ∑ i = 1 45 ( 7 i − 5 )

119.

∑ i = 1 50 ( 3 i + 6 ) ∑ i = 1 50 ( 3 i + 6 )

120.

∑ i = 1 25 ( 4 i + 3 ) ∑ i = 1 25 ( 4 i + 3 )

121.

∑ i = 1 35 ( −6 i − 2 ) ∑ i = 1 35 ( −6 i − 2 )

122.

∑ i = 1 30 ( −5 i + 1 ) ∑ i = 1 30 ( −5 i + 1 )

Writing Exercises

123.

In your own words, explain how to determine whether a sequence is arithmetic.

124.

In your own words, explain how the first two terms are used to find the tenth term. Show an example to illustrate your explanation.

125.

In your own words, explain how to find the general term of an arithmetic sequence.

126.

In your own words, explain how to find the sum of the first nn terms of an arithmetic sequence without adding all the terms.

Self Check

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

This figure shows a chart with four rows and four columns. The first row is the header row and reads, “I can”, “Confidently”, “With some help”, and “No, I don’t get it!” The column, beginning with second row reads 1. Determine if a Sequence is Arithmetic, 2. Find the General Term (nth term) of Arithmetic Sequence, and 3. Find the sum of the first Terms of an Arithmetic Sequence”. The remaining columns are blank.

ⓑ After reviewing this checklist, what will you do to become confident for all objectives?