Divide Monomials

6.5 Divide Monomials

Learning Objectives

By the end of this section, you will be able to:

  • Simplify expressions using the Quotient Property for Exponents
  • Simplify expressions with zero exponents
  • Simplify expressions using the quotient to a Power Property
  • Simplify expressions by applying several properties
  • Divide monomials

Be Prepared 6.9

Before you get started, take this readiness quiz.

Simplify: 824.824.
If you missed this problem, review Example 1.65.

Be Prepared 6.10

Simplify: (2m3)5.(2m3)5.
If you missed this problem, review Example 6.23.

Be Prepared 6.11

Simplify: 12x12y.12x12y.
If you missed this problem, review Example 1.67.

Simplify Expressions Using the Quotient Property for Exponents

Earlier in this chapter, we developed the properties of exponents for multiplication. We summarize these properties below.

Summary of Exponent Properties for Multiplication

If aandbaandb are real numbers, and mandnmandn are whole numbers, then

Product Property am·an=am+nam·an=am+n
Power Property (am)n=am·n(am)n=am·n
Product to a Power (ab)m=ambm(ab)m=ambm
This table presents fundamental properties of exponents, including product, power, and product-to-a-power rules, along with their corresponding mathematical formulas.

Now we will look at the exponent properties for division. A quick memory refresher may help before we get started. You have learned to simplify fractions by dividing out common factors from the numerator and denominator using the Equivalent Fractions Property. This property will also help you work with algebraic fractions—which are also quotients.

Equivalent Fractions Property

If a,b,andca,b,andc are whole numbers where b≠0,c≠0b≠0,c≠0,

thenab=a·cb·canda·cb·c=abthenab=a·cb·canda·cb·c=ab

As before, we’ll try to discover a property by looking at some examples.

Consider x5x2x5x2 and x2x3x2x3
What do they mean? x·x·x·x·xx·xx·x·x·x·xx·x x·xx·x·xx·xx·x·x
Use the Equivalent Fractions Property. x·x·x·x·xx·xx·x·x·x·xx·x x·x·1x·x·xx·x·1x·x·x
Simplify. x3x3 1x1x
Step-by-step simplification of rational expressions with exponents using the Equivalent Fractions Property.

Notice, in each case the bases were the same and we subtracted exponents.

When the larger exponent was in the numerator, we were left with factors in the numerator.

When the larger exponent was in the denominator, we were left with factors in the denominator—notice the numerator of 1.

We write:

x5x2x2x3x5−21x3−2x31xx5x2x2x3x5−21x3−2x31x

This leads to the Quotient Property for Exponents.

Quotient Property for Exponents

If aa is a real number, a≠0a≠0, and mandnmandn are whole numbers, then

aman=am−n,m>nandaman=1an−m,n>maman=am−n,m>nandaman=1an−m,n>m

A couple of examples with numbers may help to verify this property.

3432=34−25253=153−2819=3225125=1519=9✓15=15✓3432=34−25253=153−2819=3225125=1519=9✓15=15✓

Example 6.59

Simplify: ⓐ x9x7x9x7 ⓑ 31032.31032.

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.

  1. ⓐ
    Since 9 > 7, there are more factors of x in the numerator. x to the ninth power divided by x to the seventh power.
    Use the Quotient Property, aman=am−naman=am−n. x to the power of 9 minus 7.
    Simplify. A close-up image shows the mathematical expression 'x squared'.
  2. ⓑ
    Since 10 > 2, there are more factors of x in the numerator. 3 to the tenth power divided by 3 squared.
    Use the Quotient Property, aman=am−naman=am−n. 3 to the power of 10 minus 2.
    Simplify. 3 to the eighth power.

    Notice that when the larger exponent is in the numerator, we are left with factors in the numerator.

Try It 6.117

Simplify: ⓐ x15x10x15x10 ⓑ 61465.61465.

Try It 6.118

Simplify: ⓐ y43y37y43y37 ⓑ 1015107.1015107.

Example 6.60

Simplify: ⓐ b8b12b8b12 ⓑ 7375.7375.

Solution

To simplify an expression with a quotient, we need to first compare the exponents in the numerator and denominator.

  1. ⓐ
    Since 12 > 8, there are more factors of b in the denominator. b to the eighth power divided b to the twelfth power.
    Use the Quotient Property, aman=1an−maman=1an−m. 1 divided by b to the power of 12 minus 8.
    Simplify. 1 divided by b to the fourth power.
  2. ⓑ
    Since 5 > 3, there are more factors of 3 in the denominator. 7 cubed divided by 7 to the fifth power.
    Use the Quotient Property, aman=1an−maman=1an−m. 1 divided by 7 to the power of 5 minus 3.
    Simplify. 1 divided by 7 squared.
    Simplify. The fraction one forty-ninth is displayed, represented as 1 over 49 with a horizontal line separating the numerator and the denominator.

    Notice that when the larger exponent is in the denominator, we are left with factors in the denominator.

Try It 6.119

Simplify: ⓐ x18x22x18x22 ⓑ 12151230.12151230.

Try It 6.120

Simplify: ⓐ m7m15m7m15 ⓑ 98919.98919.

Notice the difference in the two previous examples:

  • If we start with more factors in the numerator, we will end up with factors in the numerator.
  • If we start with more factors in the denominator, we will end up with factors in the denominator.


The first step in simplifying an expression using the Quotient Property for Exponents is to determine whether the exponent is larger in the numerator or the denominator.

Example 6.61

Simplify: ⓐ a5a9a5a9 ⓑ x11x7.x11x7.

Solution

  1. ⓐ Is the exponent of aa larger in the numerator or denominator? Since 9 > 5, there are more a'sa's in the denominator and so we will end up with factors in the denominator.
    a to the fifth power divided by a to the ninth power.
    Use the Quotient Property, aman=1an−maman=1an−m. 1 divided by a to the power of 9 minus 5.
    Simplify. 1 divided by a to the fourth power.
  2. ⓑ Notice there are more factors of xx in the numerator, since 11 > 7. So we will end up with factors in the numerator.
    x to the eleventh power divided by x to the seventh power.
    Use the Quotient Property, aman=1an−maman=1an−m. x to the power of 11 minus 7.
    Simplify. x to the fourth power.

Try It 6.121

Simplify: ⓐ b19b11b19b11 ⓑ z5z11.z5z11.

Try It 6.122

Simplify: ⓐ p9p17p9p17 ⓑ w13w9.w13w9.

Simplify Expressions with an Exponent of Zero

A special case of the Quotient Property is when the exponents of the numerator and denominator are equal, such as an expression like amamamam. From your earlier work with fractions, you know that:

22=11717=1−43−43=122=11717=1−43−43=1

In words, a number divided by itself is 1. So, xx=1xx=1, for any x(x≠0)x(x≠0), since any number divided by itself is 1.

The Quotient Property for Exponents shows us how to simplify amanaman when m>nm>n and when n<mn<m by subtracting exponents. What if m=nm=n?

Consider 8888, which we know is 1.

88=188=1
Write 88 as 2323. 2323=12323=1
Subtract exponents. 23−3=123−3=1
Simplify. 20=120=1
This table illustrates the derivation of the zero exponent rule, showing step-by-step how any non-zero number raised to the power of zero equals one.

Now we will simplify amamamam in two ways to lead us to the definition of the zero exponent. In general, for a≠0a≠0:

This figure is divided into two columns. At the top of the figure, the left and right columns both contain a to the m power divided by a to the m power. In the next row, the left column contains a to the m minus m power. The right column contains the fraction m factors of a divided by m factors of a, represented in the numerator and denominator by a times a followed by an ellipsis. All the as in the numerator and denominator are canceled out. In the bottom row, the left column contains a to the zero power. The right column contains 1.

We see amamamam simplifies to a0a0 and to 1. So a0=1a0=1.

Zero Exponent

If aa is a non-zero number, then a0=1a0=1.

Any nonzero number raised to the zero power is 1.

In this text, we assume any variable that we raise to the zero power is not zero.

Example 6.62

Simplify: ⓐ 9090 ⓑ n0.n0.

Solution

The definition says any non-zero number raised to the zero power is 1.

ⓐ
Use the definition of the zero exponent.
901901
ⓑ
Use the definition of the zero exponent.
n01n01
This table demonstrates the zero exponent rule with examples, showing that any non-zero base raised to the power of zero equals one.

Try It 6.123

Simplify: ⓐ 150150 ⓑ m0.m0.

Try It 6.124

Simplify: ⓐ k0k0 ⓑ 290.290.

Now that we have defined the zero exponent, we can expand all the Properties of Exponents to include whole number exponents.

What about raising an expression to the zero power? Let’s look at (2x)0(2x)0. We can use the product to a power rule to rewrite this expression.

(2x)0(2x)0
Use the product to a power rule. 20x020x0
Use the zero exponent property. 1·11·1
Simplify. 11
Table 6.1 Step-by-step simplification of (2x)^0, illustrating the product to a power rule and zero exponent property.

This tells us that any nonzero expression raised to the zero power is one.

Example 6.63

Simplify: ⓐ (5b)0(5b)0 ⓑ (−4a2b)0.(−4a2b)0.

Solution

ⓐ (5b)0(5b)0
Use the definition of the zero exponent. 11
ⓑ (−4a2b)0(−4a2b)0
Use the definition of the zero exponent. 11
Examples demonstrating the zero exponent rule, where any non-zero base raised to the power of zero equals one.

Try It 6.125

Simplify: ⓐ (11z)0(11z)0 ⓑ (−11pq3)0.(−11pq3)0.

Try It 6.126

Simplify: ⓐ (−6d)0(−6d)0 ⓑ (−8m2n3)0.(−8m2n3)0.

Simplify Expressions Using the Quotient to a Power Property

Now we will look at an example that will lead us to the Quotient to a Power Property.

(xy)3(xy)3
This means: xy·xy·xyxy·xy·xy
Multiply the fractions. x·x·xy·y·yx·x·xy·y·y
Write with exponents. x3y3x3y3
Steps demonstrating how to expand and simplify a fraction raised to a power, showing (x/y)^3 equals x^3/y^3.

Notice that the exponent applies to both the numerator and the denominator.

We write: (xy)3(xy)3
x3y3x3y3
Illustration of the power of a quotient rule: (x/y)3 = x3/y3.

This leads to the Quotient to a Power Property for Exponents.

Quotient to a Power Property for Exponents

If aa and bb are real numbers, b≠0b≠0, and mm is a counting number, then

(ab)m=ambm(ab)m=ambm

To raise a fraction to a power, raise the numerator and denominator to that power.

An example with numbers may help you understand this property:

(23)3=233323·23·23=827827=827✓(23)3=233323·23·23=827827=827✓

Example 6.64

Simplify: ⓐ (37)2(37)2 ⓑ (b3)4(b3)4 ⓒ (kj)3.(kj)3.

Solution

ⓐ

3 sevenths squared.
Use the Quotient Property, (ab)m=ambm(ab)m=ambm. 3 squared divided by 7 squared.
Simplify. 9 forty-ninths.


ⓑ

b thirds to the fourth power.
Use the Quotient Property, (ab)m=ambm(ab)m=ambm. b to the fourth power divided by 3 to the fourth power.
Simplify. b to the fourth power divided by 81.


ⓒ

k divided by j, in parentheses, cubed.
Raise the numerator and denominator to the third power. k cubed divided by j cubed.

Try It 6.127

Simplify: ⓐ (58)2(58)2 ⓑ (p10)4(p10)4 ⓒ (mn)7.(mn)7.

Try It 6.128

Simplify: ⓐ (13)3(13)3 ⓑ (−2q)3(−2q)3 ⓒ (wx)4.(wx)4.

Simplify Expressions by Applying Several Properties

We’ll now summarize all the properties of exponents so they are all together to refer to as we simplify expressions using several properties. Notice that they are now defined for whole number exponents.

Summary of Exponent Properties

If aandbaandb are real numbers, and mandnmandn are whole numbers, then

Product Property am·an=am+nam·an=am+n
Power Property (am)n=am·n(am)n=am·n
Product to a Power (ab)m=ambm(ab)m=ambm
Quotient Property aman=am−n,a≠0,m>naman=1an−m,a≠0,n>maman=am−n,a≠0,m>naman=1an−m,a≠0,n>m
Zero Exponent Definition ao=1,a≠0ao=1,a≠0
Quotient to a Power Property (ab)m=ambm,b≠0(ab)m=ambm,b≠0
This table summarizes fundamental exponent properties, including product, power, quotient, and zero exponent rules, presented with their corresponding mathematical formulas.

Example 6.65

Simplify: (y4)2y6.(y4)2y6.

Solution

(y4)2y6(y4)2y6
Multiply the exponents in the numerator. y8y6y8y6
Subtract the exponents. y2y2
Steps to simplify the exponential expression (y^4)^2 / y^6 using exponent rules.

Try It 6.129

Simplify: (m5)4m7.(m5)4m7.

Try It 6.130

Simplify: (k2)6k7.(k2)6k7.

Example 6.66

Simplify: b12(b2)6.b12(b2)6.

Solution

b12(b2)6b12(b2)6
Multiply the exponents in the numerator. b12b12b12b12
Subtract the exponents. b0b0
Simplify. 11
This table illustrates the step-by-step simplification of the exponential expression b^12 / (b^2)^6 using exponent rules, resulting in a final value of 1.

Try It 6.131

Simplify: n12(n3)4.n12(n3)4.

Try It 6.132

Simplify: x15(x3)5.x15(x3)5.

Example 6.67

Simplify: (y9y4)2.(y9y4)2.

Solution

(y9y4)2(y9y4)2
Remember parentheses come before exponents.
Notice the bases are the same, so we can simplify
inside the parentheses. Subtract the exponents.
(y5)2(y5)2
Multiply the exponents. y10y10
This table demonstrates the step-by-step simplification of the algebraic expression (y^9 / y^4)^2, applying exponent rules for division and power of a power.

Try It 6.133

Simplify: (r5r3)4.(r5r3)4.

Try It 6.134

Simplify: (v6v4)3.(v6v4)3.

Example 6.68

Simplify: (j2k3)4.(j2k3)4.

Solution

Here we cannot simplify inside the parentheses first, since the bases are not the same.

(j2k3)4(j2k3)4
Raise the numerator and denominator to the fourth power
using the Quotient to a Power Property, (ab)m=ambm(ab)m=ambm.
Use the Power Property and simplify. j8k12j8k12
Step-by-step simplification of a rational expression using the Quotient to a Power Property and other exponent rules.

Try It 6.135

Simplify: (a3b2)4.(a3b2)4.

Try It 6.136

Simplify: (q7r5)3.(q7r5)3.

Example 6.69

Simplify: (2m25n)4.(2m25n)4.

Solution

(2m25n)4(2m25n)4
Raise the numberator and denominator to the fourth power,
using the Quotient to a Power Property, (ab)m=ambm(ab)m=ambm.
(2m2)4(5n)4(2m2)4(5n)4
Raise each factor to the fourth power. (2m2)4(5n)4(2m2)4(5n)4
Use the Power Property and simplify. 16m8625n416m8625n4
Step-by-step simplification of a rational expression raised to a power using exponent properties.

Try It 6.137

Simplify: (7x39y)2.(7x39y)2.

Try It 6.138

Simplify: (3x47y)2.(3x47y)2.

Example 6.70

Simplify: (x3)4(x2)5(x6)5.(x3)4(x2)5(x6)5.

Solution

(x3)4(x2)5(x6)5(x3)4(x2)5(x6)5
Use the Power Property, (am)n=am·n(am)n=am·n. (x12)(x10)(x30)(x12)(x10)(x30)
Add the exponents in the numerator. x22x30x22x30
Use the Quotient Property, aman=1an−maman=1an−m. 1x81x8
Step-by-step simplification of an algebraic expression using power and quotient properties of exponents.

Try It 6.139

Simplify: (a2)3(a2)4(a4)5.(a2)3(a2)4(a4)5.

Try It 6.140

Simplify: (p3)4(p5)3(p7)6.(p3)4(p5)3(p7)6.

Example 6.71

Simplify: (10p3)2(5p)3(2p5)4.(10p3)2(5p)3(2p5)4.

Solution

(10p3)2(5p)3(2p5)4(10p3)2(5p)3(2p5)4
Use the Product to a Power Property, (ab)m=ambm(ab)m=ambm. (10)2(p3)2(5)3(p)3(2)4(p5)4(10)2(p3)2(5)3(p)3(2)4(p5)4
Use the Power Property, (am)n=am·n(am)n=am·n. 100p6125p3·16p20100p6125p3·16p20
Add the exponents in the denominator. 100p6125·16p23100p6125·16p23
Use the Quotient Property, aman=1an−maman=1an−m. 100125·16p17100125·16p17
Simplify. 120p17120p17
Step-by-step simplification of a complex algebraic expression using properties of exponents.

Try It 6.141

Simplify: (3r3)2(r3)7(r3)3.(3r3)2(r3)7(r3)3.

Try It 6.142

Simplify: (2x4)5(4x3)2(x3)5.(2x4)5(4x3)2(x3)5.

Divide Monomials

You have now been introduced to all the properties of exponents and used them to simplify expressions. Next, you’ll see how to use these properties to divide monomials. Later, you’ll use them to divide polynomials.

Example 6.72

Find the quotient: 56x7÷8x3.56x7÷8x3.

Solution

56x7÷8x356x7÷8x3
Rewrite as a fraction. 56x78x356x78x3
Use fraction multiplication. 568⋅x7x3568⋅x7x3
Simplify and use the Quotient Property. 7x47x4
Steps for simplifying 56x^7 8x^3 to 7x^4, illustrating algebraic division and exponent properties.

Try It 6.143

Find the quotient: 42y9÷6y3.42y9÷6y3.

Try It 6.144

Find the quotient: 48z8÷8z2.48z8÷8z2.

Example 6.73

Find the quotient: 45a2b3−5ab5.45a2b3−5ab5.

Solution

45a2b3−5ab545a2b3−5ab5
Use fraction multiplication. 45−5·a2a·b3b545−5·a2a·b3b5
Simplify and use the Quotient Property. −9·a·1b2−9·a·1b2
Multiply. −9ab2−9ab2
Steps to simplify a rational algebraic expression using fraction multiplication and quotient properties.

Try It 6.145

Find the quotient: −72a7b38a12b4.−72a7b38a12b4.

Try It 6.146

Find the quotient: −63c8d37c12d2.−63c8d37c12d2.

Example 6.74

Find the quotient: 24a5b348ab4.24a5b348ab4.

Solution

24a5b348ab424a5b348ab4
Use fraction multiplication. 2448·a5a·b3b42448·a5a·b3b4
Simplify and use the Quotient Property. 12·a4·1b12·a4·1b
Multiply. a42ba42b
Step-by-step simplification of an algebraic rational expression using fraction multiplication and quotient properties.

Try It 6.147

Find the quotient: 16a7b624ab8.16a7b624ab8.

Try It 6.148

Find the quotient: 27p4q7−45p12q.27p4q7−45p12q.

Once you become familiar with the process and have practiced it step by step several times, you may be able to simplify a fraction in one step.

Example 6.75

Find the quotient: 14x7y1221x11y6.14x7y1221x11y6.

Solution

Be very careful to simplify 14211421 by dividing out a common factor, and to simplify the variables by subtracting their exponents.

14x7y1221x11y614x7y1221x11y6
Simplify and use the Quotient Property. 2y63x42y63x4
This table demonstrates the simplification of a rational expression using the Quotient Property, showing the original expression and its simplified form.

Try It 6.149

Find the quotient: 28x5y1449x9y12.28x5y1449x9y12.

Try It 6.150

Find the quotient: 30m5n1148m10n14.30m5n1148m10n14.

In all examples so far, there was no work to do in the numerator or denominator before simplifying the fraction. In the next example, we’ll first find the product of two monomials in the numerator before we simplify the fraction. This follows the order of operations. Remember, a fraction bar is a grouping symbol.

Example 6.76

Find the quotient: (6x2y3)(5x3y2)(3x4y5).(6x2y3)(5x3y2)(3x4y5).

Solution

(6x2y3)(5x3y2)(3x4y5)(6x2y3)(5x3y2)(3x4y5)
Simplify the numerator. 30x5y53x4y530x5y53x4y5
Simplify. 10x10x
Step-by-step simplification of a rational algebraic expression.

Try It 6.151

Find the quotient: (6a4b5)(4a2b5)12a5b8.(6a4b5)(4a2b5)12a5b8.

Try It 6.152

Find the quotient: (−12x6y9)(−4x5y8)−12x10y12.(−12x6y9)(−4x5y8)−12x10y12.

Media

Access these online resources for additional instruction and practice with dividing monomials:

Section 6.5 Exercises

Practice Makes Perfect

Simplify Expressions Using the Quotient Property for Exponents

In the following exercises, simplify.

356.

ⓐ x18x3x18x3 ⓑ 5125351253

357.

ⓐ y20y10y20y10 ⓑ 7167271672

358.

ⓐ p21p7p21p7 ⓑ 4164441644

359.

ⓐ u24u3u24u3 ⓑ 9159591595

360.

ⓐ q18q36q18q36 ⓑ 102103102103

361.

ⓐ t10t40t10t40 ⓑ 83858385

362.

ⓐ bb9bb9 ⓑ 446446

363.

ⓐ xx7xx7 ⓑ 1010310103

Simplify Expressions with Zero Exponents

In the following exercises, simplify.

364.

ⓐ 200200 ⓑ b0b0

365.

ⓐ 130130 ⓑ k0k0

366.

ⓐ −270−270 ⓑ −(270)−(270)

367.

ⓐ −150−150 ⓑ −(150)−(150)

368.

ⓐ (25x)0(25x)0 ⓑ 25x025x0

369.

ⓐ (6y)0(6y)0 ⓑ 6y06y0

370.

ⓐ (12x)0(12x)0 ⓑ (−56p4q3)0(−56p4q3)0

371.

ⓐ 7y07y0(17y)0(17y)0 ⓑ (−93c7d15)0(−93c7d15)0

372.

ⓐ 12n0−18m012n0−18m0 ⓑ (12n)0−(18m)0(12n)0−(18m)0

373.

ⓐ 15r0−22s015r0−22s0 ⓑ (15r)0−(22s)0(15r)0−(22s)0

Simplify Expressions Using the Quotient to a Power Property

In the following exercises, simplify.

374.

ⓐ (34)3(34)3 ⓑ (p2)5(p2)5 ⓒ (xy)6(xy)6

375.

ⓐ (25)2(25)2 ⓑ (x3)4(x3)4 ⓒ (ab)5(ab)5

376.

ⓐ (a3b)4(a3b)4 ⓑ (54m)2(54m)2

377.

ⓐ (x2y)3(x2y)3 ⓑ (103q)4(103q)4

Simplify Expressions by Applying Several Properties

In the following exercises, simplify.

378.

( a 2 ) 3 a 4 ( a 2 ) 3 a 4

379.

( p 3 ) 4 p 5 ( p 3 ) 4 p 5

380.

( y 3 ) 4 y 10 ( y 3 ) 4 y 10

381.

( x 4 ) 5 x 15 ( x 4 ) 5 x 15

382.

u 6 ( u 3 ) 2 u 6 ( u 3 ) 2

383.

v 20 ( v 4 ) 5 v 20 ( v 4 ) 5

384.

m 12 ( m 8 ) 3 m 12 ( m 8 ) 3

385.

n 8 ( n 6 ) 4 n 8 ( n 6 ) 4

386.

( p 9 p 3 ) 5 ( p 9 p 3 ) 5

387.

( q 8 q 2 ) 3 ( q 8 q 2 ) 3

388.

( r 2 r 6 ) 3 ( r 2 r 6 ) 3

389.

( m 4 m 7 ) 4 ( m 4 m 7 ) 4

390.

( p r 11 ) 2 ( p r 11 ) 2

391.

( a b 6 ) 3 ( a b 6 ) 3

392.

( w 5 x 3 ) 8 ( w 5 x 3 ) 8

393.

( y 4 z 10 ) 5 ( y 4 z 10 ) 5

394.

( 2 j 3 3 k ) 4 ( 2 j 3 3 k ) 4

395.

( 3 m 5 5 n ) 3 ( 3 m 5 5 n ) 3

396.

( 3 c 2 4 d 6 ) 3 ( 3 c 2 4 d 6 ) 3

397.

( 5 u 7 2 v 3 ) 4 ( 5 u 7 2 v 3 ) 4

398.

( k 2 k 8 k 3 ) 2 ( k 2 k 8 k 3 ) 2

399.

( j 2 j 5 j 4 ) 3 ( j 2 j 5 j 4 ) 3

400.

( t 2 ) 5 ( t 4 ) 2 ( t 3 ) 7 ( t 2 ) 5 ( t 4 ) 2 ( t 3 ) 7

401.

( q 3 ) 6 ( q 2 ) 3 ( q 4 ) 8 ( q 3 ) 6 ( q 2 ) 3 ( q 4 ) 8

402.

( −2 p 2 ) 4 ( 3 p 4 ) 2 ( −6 p 3 ) 2 ( −2 p 2 ) 4 ( 3 p 4 ) 2 ( −6 p 3 ) 2

403.

( −2 k 3 ) 2 ( 6 k 2 ) 4 ( 9 k 4 ) 2 ( −2 k 3 ) 2 ( 6 k 2 ) 4 ( 9 k 4 ) 2

404.

( −4 m 3 ) 2 ( 5 m 4 ) 3 ( −10 m 6 ) 3 ( −4 m 3 ) 2 ( 5 m 4 ) 3 ( −10 m 6 ) 3

405.

( −10 n 2 ) 3 ( 4 n 5 ) 2 ( 2 n 8 ) 2 ( −10 n 2 ) 3 ( 4 n 5 ) 2 ( 2 n 8 ) 2

Divide Monomials

In the following exercises, divide the monomials.

406.

56 b 8 ÷ 7 b 2 56 b 8 ÷ 7 b 2

407.

63 v 10 ÷ 9 v 2 63 v 10 ÷ 9 v 2

408.

−88 y 15 ÷ 8 y 3 −88 y 15 ÷ 8 y 3

409.

−72 u 12 ÷ 1 2 u 4 −72 u 12 ÷ 1 2 u 4

410.

45 a 6 b 8 −15 a 10 b 2 45 a 6 b 8 −15 a 10 b 2

411.

54 x 9 y 3 −18 x 6 y 15 54 x 9 y 3 −18 x 6 y 15

412.

15 r 4 s 9 18 r 9 s 2 15 r 4 s 9 18 r 9 s 2

413.

20 m 8 n 4 30 m 5 n 9 20 m 8 n 4 30 m 5 n 9

414.

18 a 4 b 8 −27 a 9 b 5 18 a 4 b 8 −27 a 9 b 5

415.

45 x 5 y 9 −60 x 8 y 6 45 x 5 y 9 −60 x 8 y 6

416.

64 q 11 r 9 s 3 48 q 6 r 8 s 5 64 q 11 r 9 s 3 48 q 6 r 8 s 5

417.

65 a 10 b 8 c 5 42 a 7 b 6 c 8 65 a 10 b 8 c 5 42 a 7 b 6 c 8

418.

( 10 m 5 n 4 ) ( 5 m 3 n 6 ) 25 m 7 n 5 ( 10 m 5 n 4 ) ( 5 m 3 n 6 ) 25 m 7 n 5

419.

( −18 p 4 q 7 ) ( −6 p 3 q 8 ) −36 p 12 q 10 ( −18 p 4 q 7 ) ( −6 p 3 q 8 ) −36 p 12 q 10

420.

( 6 a 4 b 3 ) ( 4 a b 5 ) ( 12 a 2 b ) ( a 3 b ) ( 6 a 4 b 3 ) ( 4 a b 5 ) ( 12 a 2 b ) ( a 3 b )

421.

( 4 u 2 v 5 ) ( 15 u 3 v ) ( 12 u 3 v ) ( u 4 v ) ( 4 u 2 v 5 ) ( 15 u 3 v ) ( 12 u 3 v ) ( u 4 v )

Mixed Practice

422.

ⓐ 24a5+2a524a5+2a5 ⓑ 24a5−2a524a5−2a5 ⓒ 24a5·2a524a5·2a5 ⓓ 24a5÷2a524a5÷2a5

423.

ⓐ 15n10+3n1015n10+3n10 ⓑ 15n10−3n1015n10−3n10 ⓒ 15n10·3n1015n10·3n10 ⓓ 15n10÷3n1015n10÷3n10

424.

ⓐ p4·p6p4·p6 ⓑ (p4)6(p4)6

425.

ⓐ q5·q3q5·q3 ⓑ (q5)3(q5)3

426.

ⓐ y3yy3y ⓑ yy3yy3

427.

ⓐ z6z5z6z5 ⓑ z5z6z5z6

428.

( 8 x 5 ) ( 9 x ) ÷ 6 x 3 ( 8 x 5 ) ( 9 x ) ÷ 6 x 3

429.

( 4 y ) ( 12 y 7 ) ÷ 8 y 2 ( 4 y ) ( 12 y 7 ) ÷ 8 y 2

430.

27 a 7 3 a 3 + 54 a 9 9 a 5 27 a 7 3 a 3 + 54 a 9 9 a 5

431.

32 c 11 4 c 5 + 42 c 9 6 c 3 32 c 11 4 c 5 + 42 c 9 6 c 3

432.

32 y 5 8 y 2 − 60 y 10 5 y 7 32 y 5 8 y 2 − 60 y 10 5 y 7

433.

48 x 6 6 x 4 − 35 x 9 7 x 7 48 x 6 6 x 4 − 35 x 9 7 x 7

434.

63 r 6 s 3 9 r 4 s 2 − 72 r 2 s 2 6 s 63 r 6 s 3 9 r 4 s 2 − 72 r 2 s 2 6 s

435.

56 y 4 z 5 7 y 3 z 3 − 45 y 2 z 2 5 y 56 y 4 z 5 7 y 3 z 3 − 45 y 2 z 2 5 y

Everyday Math

436.

Memory One megabyte is approximately 106106 bytes. One gigabyte is approximately 109109 bytes. How many megabytes are in one gigabyte?

437.

Memory One gigabyte is approximately 109109 bytes. One terabyte is approximately 10121012 bytes. How many gigabytes are in one terabyte?

Writing Exercises

438.

Jennifer thinks the quotient a24a6a24a6 simplifies to a4a4. What is wrong with her reasoning?

439.

Maurice simplifies the quotient d7dd7d by writing d7d=7d7d=7. What is wrong with his reasoning?

440.

When Drake simplified −30−30 and (−3)0(−3)0 he got the same answer. Explain how using the Order of Operations correctly gives different answers.

441.

Robert thinks x0x0 simplifies to 0. What would you say to convince Robert he is wrong?

Self Check

ⓐ After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

This is a table that has six rows and four columns. In the first row, which is a header row, the cells read from left to right “I can…,” “Confidently,” “With some help,” and “No-I don’t get it!” The first column below “I can…” reads “simplify expressions using the Quotient Property for Exponents,” “simplify expressions with zero exponents,” “simplify expressions using the Quotient to a Power Property,” “simplify expressions by applying several properties,” and “divide monomials.” The rest of the cells are blank.

ⓑ On a scale of 1-10, how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?