$64÷\left(2\cdot 8\right)+14÷7$

$5x+9=\mathrm{-11}$

$9\left(y+2\right)÷3\cdot 2+1$

11

$\frac{5}{6}$

$2^2\cdot 2^4$

${\left(\frac{a^2}{b^3}\right)}^4$

$\frac{{\left(xy\right)}^4}{y^3}\cdot \frac{2}{x^5}$

${\left(\frac{2x^2}{y}\right)}^{\mathrm{-2}}$

Write the number in standard notation: $2.1314\times {10}^{\mathrm{-6}}$

$\sqrt{121}$

$\sqrt{361}$

$\sqrt{162}$

$\sqrt{\frac{80}{81}}$

$\frac{2}{4+\sqrt{2}}$

$12\sqrt{5}-13\sqrt{5}$

$\frac{\sqrt[3]{250}}{\sqrt[3]{\mathrm{-8}}}$

$\left(2y+1\right)-\left(2y^2-2y-5\right)$

$\left(6a^2+3a+10\right)-\left(6a^2\mathrm{-3}a+5\right)$

$(2h+1)(3h-2)$

$(m-2)(m^2+2m-3)$

$\left(x+y\right)\left(x-y\right)$

$12x^{2}y+4x{y}^2\mathrm{-18}xy$

$2x^2-9x-18$

$d^2-5d-66$

$y^2-6y+9$

$361x^2-121$

$8x^3-125$

$4x{(x-1)}^{-\frac{1}{4}}+3{(x-1)}^{\frac{3}{4}}$

$4r{\left(2r-1\right)}^{-\frac{2}{3}}-5{\left(2r-1\right)}^{\frac{1}{3}}$

$\frac{4y^2-25}{4y^2-20y+25}$

$\frac{d-4}{d^2-9}\cdot \frac{d-3}{d^2-16}$

$\frac{4d^2-7d-2}{6d^2-17d+10}÷\frac{8d^2+6d+1}{6d^2+7d-10}$

$\frac{12}{a^2+2a+1}-\frac{3}{a^2\mathrm{-1}}$

$\frac{\frac{3}{x}-\frac{7}{y}}{\frac{2}{x}}$