$y-\frac{1}{3}=\frac{5}{12}$:

1. ⓐ $y=1$
2. ⓑ $y=\frac{3}{4}$
3. ⓒ $y=-\frac{3}{4}$

$k+\frac{2}{5}=\frac{5}{6}$:

1. ⓐ $k=1$
2. ⓑ $k=\frac{13}{30}$
3. ⓒ $k=-\frac{13}{30}$

$m+\frac{3}{8}=\frac{7}{8}$

$h+\frac{5}{6}=\frac{1}{6}$

$c-\frac{1}{4}=-\frac{5}{4}$

$z-\left(-\frac{5}{12}\right)=-\frac{7}{12}$

$p-\frac{3}{10}=\frac{5}{8}$

$k+\left(-\frac{1}{3}\right)=-\frac{4}{5}$

$7k=18$

$\mathrm{-9}v=33$

$\frac{b}{3}=\mathrm{-9}$

$\frac{x}{8}=\mathrm{-32}$

$\frac{q}{\mathrm{-4}}=\mathrm{-40}$

$\frac{s}{\mathrm{-15}}=\mathrm{-3}$

$-y=42$

$-k=-\frac{17}{20}$

$\frac{3}{10}p=30$

$\frac{5}{2}m=\mathrm{-40}$

$-\frac{3}{7}b=9$

$-\frac{5}{12}v=\mathrm{-15}$

$8y=0$

$7g=\frac{7}{9}$

$q+\frac{5}{6}=\frac{1}{12}$

$\frac{1}{4}n=\frac{7}{10}$

$-\frac{2}{3}=y+\frac{3}{8}$

$\frac{8}{15}=-\mathit{\text{d}}$

$n$ divided by six is $\mathrm{-24}.$

$m$ divided by $\mathrm{-7}$ is $\mathrm{-8}.$

The quotient of $f$ and $\mathrm{-4}$ is $\mathrm{-20}.$

The quotient of $g$ and nine is $14.$

Two-fifths of $q$ is $20.$

Four-ninths of $p$ is $\mathrm{-28}.$

The quotient of $h$ and $2$ is $43.$

The quotient of $a$ and $\frac{2}{3}$ is $\frac{3}{4}.$

The sum of three-fourths and $x$ is $\frac{1}{8}.$

The difference of $y$ and one-third is $-\frac{1}{6}.$