Key Equations

Key Equations

Relationship between frequency and period f=1Tf=1T
Position in SHM withϕ=0.00Position in SHM withϕ=0.00 x(t)=Acos(ωt)x(t)=Acos(ωt)
General position in SHM x(t)=Acos(ωt+ϕ)x(t)=Acos(ωt+ϕ)
General velocity in SHM v(t)=−Aωsin(ωt+ϕ)v(t)=−Aωsin(ωt+ϕ)
General acceleration in SHM a(t)=−Aω2cos(ωt+ϕ)a(t)=−Aω2cos(ωt+ϕ)
Maximum displacement (amplitude) of SHM xmax=Axmax=A
Maximum velocity of SHM |vmax|=Aω|vmax|=Aω
Maximum acceleration of SHM |amax|=Aω2|amax|=Aω2
Angular frequency of a mass-spring system in SHM ω=kmω=km
Period of a mass-spring system in SHM T=2πmkT=2πmk
Frequency of a mass-spring system in SHM f=12πkmf=12πkm
Energy in a mass-spring system in SHM ETotal=12kx2+12mv2=12kA2ETotal=12kx2+12mv2=12kA2
The velocity of the mass in a spring-mass
system in SHM
v=±km(A2−x2)v=±km(A2−x2)
The x-component of the radius of a rotating disk x(t)=Acos(ωt+ϕ)x(t)=Acos(ωt+ϕ)
The x-component of the velocity of the edge of a rotating disk v(t)=−vmaxsin(ωt+ϕ)v(t)=−vmaxsin(ωt+ϕ)
The x-component of the acceleration of the
edge of a rotating disk
a(t)=−amaxcos(ωt+ϕ)a(t)=−amaxcos(ωt+ϕ)
Force equation for a simple pendulum d2θdt2=−gLθd2θdt2=−gLθ
Angular frequency for a simple pendulum ω=gLω=gL
Period of a simple pendulum T=2πLgT=2πLg
Angular frequency of a physical pendulum ω=mgLIω=mgLI
Period of a physical pendulum T=2πImgLT=2πImgL
Period of a torsional pendulum T=2πIκT=2πIκ
Newton’s second law for harmonic motion md2xdt2+bdxdt+kx=0md2xdt2+bdxdt+kx=0
Solution for underdamped harmonic motion x(t)=A0e−b2mtcos(ωt+ϕ)x(t)=A0e−b2mtcos(ωt+ϕ)
Natural angular frequency of a
mass-spring system
ω0=kmω0=km
Angular frequency of underdamped
harmonic motion
ω=ω02−(b2m)2ω=ω02−(b2m)2
Newton’s second law for forced,
damped oscillation
−kx−bdxdt+Fosin(ωt)=md2xdt2−kx−bdxdt+Fosin(ωt)=md2xdt2
Solution to Newton’s second law for forced,
damped oscillations
x(t)=Acos(ωt+ϕ)x(t)=Acos(ωt+ϕ)
Amplitude of system undergoing forced,
damped oscillations
A=Fom2(ω2−ωo2)2+b2ω2A=Fom2(ω2−ωo2)2+b2ω2